Respuesta :

jainanuj
4 moles of HCl are produced by 1 mole of SiCl4

2.7 moles of HCl will be produced if we have

2.7/4=0.675moles of SiCl4

molecular weight of SiCl4 =169.9g

amount of SiCl4 needed = 169.9 X 0.675=114.682g

114.682 g is the answer

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