chelseasanzo
chelseasanzo
04-08-2017
Mathematics
contestada
^^^^^^ need help with these
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irspow
irspow
04-08-2017
Always look at the prime factorization of the numbers under the radical signs to know what can be moved out from under the radical sign...
√8+3√2+√32 so
√(2*2*2)+3√2+√(2*2*2*2*2) so upon removing the perfects squares...
2√2+3√2+4√2 which is
(2+3+4)√2
9√2
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koziadam
koziadam
04-08-2017
√8 + 3√2 + √32
√2*4 + 3√2 + √4*8
√2√4 + 3√2 + √4√8
2√2 + 3√2 + 2√8
2√2 + 3√2 + 2√2*4
2√2 + 3√2 + 2√2√4
2√2 + 3√2 + 2(2)√2
2√2 + 3√2 + 4√2
9√2
Therefore the third option is correct.
It's just factoring and adding like terms
Answer Link
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