Respuesta :

2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O

m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}

m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)

m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g

131.7 grams of carbon dioxide would be formed

The answer is 131.0 g CO2