Solve: 7+15e^(1-3x)=10

Question

02-03-2017
Mathematics

contestada

Solve: 7+15e^(1-3x)=10

Respuesta :

Otras preguntas

Ava, Grace, Jayden, and Zoe together stacked a total of 50 brownies on a tray. Ava stacked 0.14 of the brownies, Grace stacked 4 of the 50 brownies, Jayden stac

3/9 in simplest form

Write x2 − 2x − 3 = 0 in the form (x − a)2 = b, where a and b are integers. (A) (x − 4)2 = 3 (B) (x − 3)2 = 2 (C) (x − 2)2 = 1 (D)(x − 1)2 = 4

How does the rate of a proportional tax change with income? A) The rate increases as income increases. B) The rate remains the same, even if income increases or

how do you solve this?

Which unit of measurement would be the most appropriate to measure the capacity of a large vase? A : milligram B : liter C : kilogram D : kiloliter

Which sentence is punctuated correctly? A. That piece of furniture is made of three types of wood pine, oak, and cedar. B. This warm-up exercise is useful for

Multiply. 2/7 x 35 =

The test scores for a group of students are shown. 87, 72, 98, 84, 72, 65, 72, 70, 58, 91, 81, 84 What is the mode of the scores? A. 84 B. 78.8 C. 98 D.

What is 18 times 12 for baseball cards

chul chul · Answer 1 · 2017-03-02T23:27:40+01:00

So I am going to assume this is a logic problem.

15(2.718282[tex] ^{−3x+1} [/tex]) + 7 = 10

Subtract 7 from both sides.

15(2.718282[tex] ^{−3x+1} [/tex]) = 3

Divide both sides by 15.

[tex] \frac{15(2.72.718282 ^{−3x+1}}{15} = \frac{3}{15} [/tex]

2.718282[tex] ^{-3x+1} [/tex] = [tex] \frac{1}{5} [/tex]

Now you solve for the exponent.

(Take log of both sides)

(−3x+1)*(log(2.718282))=log(1/5)

−3x+1 = [tex] \frac{log \frac{1}{5} }{log(2.718282) } [/tex]

−3x+1=−1.609438

−3x+1−1=−1.609438−1(Subtract 1 from both sides)

−3x=−2.609438 (divide 3 on both sides)

Answer:

x = 0.869813

or...

Rounded Answer:
0.87