Mtrollope Mtrollope

02-09-2021
Physics

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When wile coyote is launched his velocity is 20 m/s. As a slightly underweight 10kg coyote, how far would the 400 N/m spring have been stretched to give him this speed?

Respuesta :

02-09-2021

Answer:

E = 1/2 m v^2 = 1/2 k x^2 equating KE of coyote and spring

x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m

x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2

x = 3.16 m

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