Answer:
this is going to be alot i am very sorry. i had to put it like that im sorry
Step-by-step explanation:
As
a
3
+
b
3
=
(
a
+
b
)
(
a
2
+
b
2
−
a
b
)
8
(
sin
6
P
+
cos
6
P
)
=
8
(
sin
2
P
+
cos
2
P
)
(
sin
4
P
+
cos
4
P
−
sin
2
P
cos
2
P
)
=
8
(
sin
4
P
+
cos
4
P
+
2
sin
2
P
cos
2
P
−
3
sin
2
P
cos
2
P
)
=
8
(
(
sin
2
P
+
cos
2
P
)
2
−
3
sin
2
P
cos
2
P
)
=
8
(
1
−
3
4
(
4
sin
2
P
cos
2
P
)
)
=
8
−
6
sin
2
2
P
=
8
−
6
(
1
−
cos
2
2
P
)
=
2
+
6
cos
2
2
P
As
cos
4
P
=
2
cos
2
2
P
−
1
, we have
cos
2
2
P
=
1
+
cos
4
P
2
Hence,
8
(
sin
6
P
+
cos
6
P
)
=
2
+
6
×
1
+
cos
4
P
2
=
2
+
6
2
+
3
cos
4
P
=
5
+
3
cos
4
P
