Answer:
The answer is "[tex]\pi \int^{h}_{0}(\frac{r}{h} x)^2 \ dx[/tex]"
Step-by-step explanation:
[tex]dv=(Area) \ thickness[/tex]
[tex]=\pi r^2 \ dx\\\\=\pi (\frac{r}{h} x)^2 \ dx[/tex]
[tex]V= \int^{h}_{0} \pi (\frac{r}{h} x)^2 \ dx\\\\[/tex]
[tex]=\pi \int^{h}_{0}(\frac{r}{h} x)^2 \ dx[/tex]
