emma1804 emma1804
  • 02-02-2021
  • Mathematics
contestada

For the function f(x) = -4x^2 + 8x+8, find the slope of the tangent line at
X = -3.

For the function fx 4x2 8x8 find the slope of the tangent line at X 3 class=

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ngoa1575 ngoa1575
  • 02-02-2021

Answer:

Find the corresponding y-value to x=−3.

Substitute −3 in for x.

y=−4(−3)²+8(−3)+8

Simplify −4(−3)²+8(−3)+8

y=−36−24+8 => y=−52

Find the first derivative and evaluate at x=−3 and y=−52 to find the slope of the tangent line.

Plug the slope and point values into the point-slope formula and solve for y

y=32x+44

Step-by-step explanation:

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