Answer:
Step-by-step explanation:
hello,
I assume that you mean
[tex]h(x)=\dfrac{12}{x-1}[/tex]
so first of all let's take x real different from 1 , as this is not allowed to divide by 0
[tex](hoh^{-1})(x)=x=h(h^{-1}(x))=\dfrac{12}{h^{-1}(x)-1} \ \ \ so\\h^{-1}(x)-1=\dfrac{12}{x} \\\\h^{-1}(x)=1+\dfrac{12}{x}[/tex]
and this is defined for x real different from 0
hope this helps
