Answer:
133 mL
Explanation:
M= mol solute/ L solution
mol solute= M *L solution
mol solute = (2.0 M * 0.4 L)
mol solute= 0.8 mol HCl= mol H
We need the same amount of OH moles to neutralize the solution
L solution = mol solute/M
L solution= 0.8 mol Ba(OH)2/ 6M
L solution=0.133 L=133 mL
