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caylus
One year later,

You have not understood my wrong answer!

[tex]6 \dfrac{1}{3} +4 \dfrac{3}{4}+3 \dfrac{7}{12} \\ =(6+ \dfrac{1}{3} )+(4+ \dfrac{3}{4})+(3+ \dfrac{7}{12} )\\\\ =(6+4+3)+( \dfrac{1}{3} + \dfrac{3}{4} + \dfrac{7}{12} )\\\\ =13+ \dfrac{4+9+7}{12} =13 \dfrac{20}{12} =13+1+ \dfrac{8}{12} \\\\ =14+ \dfrac{2}{3} =14 \dfrac{2}{3} [/tex]

Is it more clear?

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